At the outer edge of a rotating space habitat, 130 m from its center, the rotational acceleration is g. What is the rotational acceleration at a distance of 65 m from the center of the habitat?

Question

anonymous · Answer

Is "g" one G-force? Or do you need to give the answer in terms of g?

anonymous · Answer

(do you need to use 'g' as a variable)?

anonymous · Answer

am not shure

anonymous · Answer

I'm sorry, I just realised that it makes no difference.

Have you seen the formula: $$a_c = \frac{v^2}{r}$$

anonymous · Answer

first time seeing it

anonymous · Answer

Okay, to me this is a physics question but there may well be a more mathematical way of doing it. I will show you the way that I know

anonymous · Answer

its a physics question

anonymous · Answer

$$a_c=\frac{v^2}{r}$$

From the first part of the statement, we know the acceleration and radius so we can fill that in for the formula.
$$g=\frac{v^2}{130}$$
Therefore $$v^2=130g$$

Now we know the value of v^2, and from the second part of the statement we know the radius and that means we can use this to solve for the acceleration.

$$a_c=\frac{v^2}{r}$$
$$a_c=\frac{130g}{65}$$
$$a_c=2g$$

Therefore the acceleration is 2g, or 2Gs (if g is a unit)

anonymous · Answer

For specifically physics questions, there is a physics part of open study that may be able to help you more. I have just taken physics in highschool so I knew how to do it :)

anonymous · Answer

thank you :) could you help me out with one more question?

anonymous · Answer

I'll do my best

anonymous · Answer

I have to go now, sorry. Asking in the physics openstudy section will probably give you the best luck

anonymous · Answer

Sorry computer kept on freezing