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OpenStudy (dawnr):
Help people!
The coefficient of x^24 in the advanced level of binomial form (x^2- 2x)^13 is?
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OpenStudy (dawnr):
@yamyam70
OpenStudy (yamyam70):
wait up bro ..
OpenStudy (dawnr):
waiting! :D
OpenStudy (yamyam70):
|dw:1403616200681:dw|
OpenStudy (dawnr):
okay
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OpenStudy (yamyam70):
x^24 man is the given problem correct? I can't work this out. x^24 alone has a coefficient 1. I don't get the part of the binomial
OpenStudy (dawnr):
it should be expanded somehow
OpenStudy (dawnr):
idk xD
the correct answer should be 312 but i don't know how to get there
OpenStudy (yamyam70):
okay lets expand ,
OpenStudy (yamyam70):
|dw:1403616747001:dw|
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OpenStudy (dawnr):
lovely :D
OpenStudy (yamyam70):
well a great source of anxiety, its the perfect example. Goodluck on this one :D
OpenStudy (dawnr):
ahaha (Y) :D anxiety <3
OpenStudy (dawnr):
@ShadowLegendX
OpenStudy (dawnr):
@razor99 @tanya123 @SarahEZZMcK @Jim766 @Somy
can someone help?! :O
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OpenStudy (somy):
sorry T_T idk
OpenStudy (dawnr):
:/
i can't anyone who can solve this x_0
OpenStudy (dawnr):
if you know someone tag them here..
OpenStudy (dawnr):
@ganeshie8
ganeshie8 (ganeshie8):
can you write the nth term of binomial expansion ?
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OpenStudy (dawnr):
..no :|
ganeshie8 (ganeshie8):
knw the binomial theorem ?
ganeshie8 (ganeshie8):
\[\large (a+b)^n = \sum \limits_{k=1}^n \binom{n}{k} a^{n-k}b^k\]
ganeshie8 (ganeshie8):
seen that before, right ?
OpenStudy (dawnr):
yea i did
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ganeshie8 (ganeshie8):
good, express the given binomial power as above ^
ganeshie8 (ganeshie8):
\(\large (x^2- 2x)^{13}\)
\(a = x^2\)
\(b = -2x\)
\(n = 13\)
ganeshie8 (ganeshie8):
plugin
ganeshie8 (ganeshie8):
\[\large (x^2 -2x)^{13} = \sum \limits_{k=1}^{13} \binom{13}{k} (x^2)^{13-k}(-2x)^k\]
ganeshie8 (ganeshie8):
\[\large ~~~ = \sum \limits_{k=1}^{13} \binom{13}{k} (x)^{26-2k}(x)^k(-2)^k\]
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ganeshie8 (ganeshie8):
\[\large ~~~ = \sum \limits_{k=1}^{13} \binom{13}{k} (x)^{26-2k+k}(-2)^k\]
ganeshie8 (ganeshie8):
\[\large ~~~ = \sum \limits_{k=1}^{13} \binom{13}{k} (x)^{26-k}(-2)^k\]
ganeshie8 (ganeshie8):
Alright, looks like we're ready, what are we trying to find here ?
OpenStudy (dawnr):
the coefficient of x^24 sorry i didn't apply right away i had to go to the market
ganeshie8 (ganeshie8):
thats okay, so when do we get the x^24 ?
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ganeshie8 (ganeshie8):
26 - k = 24
solve k
OpenStudy (dawnr):
the correct answer should be 312 o.O
ganeshie8 (ganeshie8):
we're not done yet,
solve k first
OpenStudy (dawnr):
k=2
ganeshie8 (ganeshie8):
plugin k=2 in the formula and find the coefficient
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ganeshie8 (ganeshie8):
k=2
that means the second term has a degree of 24 :
\[\large ~~~ = \binom{13}{2} (x)^{26-2}(-2)^2 \]
ganeshie8 (ganeshie8):
simplify
OpenStudy (dawnr):
so i got \[\left(\begin{matrix}13 \\ 2\end{matrix}\right) (x)^{24} (4) and \left(\begin{matrix}13 \\ 2\end{matrix}\right)=78\]
ganeshie8 (ganeshie8):
multiply it by 4
OpenStudy (dawnr):
312x^24 :)
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ganeshie8 (ganeshie8):
Yes !