Question

Using the following equation:

2 NaOH + H2SO4  2 H2O + Na2SO4

How many grams of sodium sulfate will be formed if you start with 200
grams of sodium hydroxide and you have an excess of sulfuric acid?

Answer 1

Number of Moles Could be Calculated using the equation
Mass(g)/Molar Mass(g/mol)
Molar Mass of Sodium hydroxide:(23*1)+(16*1)+(1*1)=40g/mol
200/40= 5moles of sodium hydroxide
Ratio of Moles of NaOH to Na2SO4 is 2:1
so 5 moles of NaOH reacts then 5*1/2 of Sodium sulphate are produced.

Answer 2

Molar Mass of Sodium Sulphate: 142 g/mol
2.5=Mass/142
Mass=142*2.5-355grams

Answer 3

@Abmon98 it's great you know how to do this, but you should let them work the final answer out - explaining it is good enough.