When magnesium metal and an aqueous solution of hydrochloric acid combine, they produce an aqueous solution of magnesium chloride and hydrogen gas. Using the equation, Mg (s) + 2HCl (aq) arrow MgCl2 (aq) + H2 (g), if 24.3 g of Mg and 75.0 g of HCl are allowed to react, calculate the mass of H2 that is produced.
@Preetha
@dan815
@1800_RATCHETHUNTERS
idk mane
fine, fine...:)
Can you calculate the number of moles first?
for what?
For 24.3 grams of magnesium and 75.0 grams of hydrochloric acid?
yes, I'm trying to figure that out now finding molar mass confuses me
my friend's dad, who's a chemical engineer, says it's atomic weight?
yup
ok....but for 2HCI..do I find the atomic weights of H and CI, add them, and multiply the sum to find the molar mas?
sorry, multiply the sum by 2
do not multiply the sum by anything. You have 75 grams of HCl. One mole of HCl has ? grams. The number of moles of HCl, thus, is 75/?
since it's 2HCI
ohhh....ok... so I need to find how many grams HCI has
brb
H = 1 gram. Cl = 35.45 grams.
k..so that makes it 75/(1 + 35.45)
75/(36.45)
2
HCI's molar mass is 2?
No, the number of moles of HCl is 2.
oh, right, right
MG wouldn't happen to have one mole would it?
It would, because the mass of one mole of Mg is 24.3 g (that's the definition of molar mass).
woohoo OK, now I have to find out what the original question was, lol :) thnx btw for your help
Now that you have the number of moles, do you know how to analyse reactions? I'll give you a simple example.\[\rm 2Mg + O_2 \to 2MgO\]This means that for every two moles of Mg and every one mole of O, you get two moles of MgO.
OK...
So in our reaction, can you think of the number of moles of \(\rm H_2\) using the same logic?
ummm.....one....?
it can't be more than 3 can it?
so it has to be either one or two...I would imagine.. my brain does not want to process this...work, dammit, WORKK!!
\[\rm Mg + 2HCl \to MgCl_2+H_2\]If you have one mole of magnesium and two moles of hydrochloric acid, you're gonna get one mole of \(\rm MgCl_2\) and one mole of \(\rm H_2\). Do you understand why that is?
well...kinda...I would have expected that you'd get 2 moles of MgCI2 though...
Here is how I understood this: First, clear your mind. Second, think about this carefully: If one molecule of Mg reacts with two molecules of HCl, then you would get one molecule of \(\rm MgCl_2\) and one molecule of \(\rm H_2\). Do you agree with the above to start with?
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