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OpenStudy (anonymous):

When magnesium metal and an aqueous solution of hydrochloric acid combine, they produce an aqueous solution of magnesium chloride and hydrogen gas. Using the equation, Mg (s) + 2HCl (aq) arrow MgCl2 (aq) + H2 (g), if 24.3 g of Mg and 75.0 g of HCl are allowed to react, calculate the mass of H2 that is produced.

OpenStudy (anonymous):

@Preetha

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@1800_RATCHETHUNTERS

OpenStudy (anonymous):

idk mane

OpenStudy (anonymous):

fine, fine...:)

OpenStudy (anonymous):

Can you calculate the number of moles first?

OpenStudy (anonymous):

for what?

OpenStudy (anonymous):

For 24.3 grams of magnesium and 75.0 grams of hydrochloric acid?

OpenStudy (anonymous):

yes, I'm trying to figure that out now finding molar mass confuses me

OpenStudy (anonymous):

my friend's dad, who's a chemical engineer, says it's atomic weight?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

ok....but for 2HCI..do I find the atomic weights of H and CI, add them, and multiply the sum to find the molar mas?

OpenStudy (anonymous):

sorry, multiply the sum by 2

OpenStudy (anonymous):

do not multiply the sum by anything. You have 75 grams of HCl. One mole of HCl has ? grams. The number of moles of HCl, thus, is 75/?

OpenStudy (anonymous):

since it's 2HCI

OpenStudy (anonymous):

ohhh....ok... so I need to find how many grams HCI has

OpenStudy (anonymous):

brb

OpenStudy (anonymous):

H = 1 gram. Cl = 35.45 grams.

OpenStudy (anonymous):

k..so that makes it 75/(1 + 35.45)

OpenStudy (anonymous):

75/(36.45)

OpenStudy (anonymous):

2

OpenStudy (anonymous):

HCI's molar mass is 2?

OpenStudy (anonymous):

No, the number of moles of HCl is 2.

OpenStudy (anonymous):

oh, right, right

OpenStudy (anonymous):

MG wouldn't happen to have one mole would it?

OpenStudy (anonymous):

It would, because the mass of one mole of Mg is 24.3 g (that's the definition of molar mass).

OpenStudy (anonymous):

woohoo OK, now I have to find out what the original question was, lol :) thnx btw for your help

OpenStudy (anonymous):

Now that you have the number of moles, do you know how to analyse reactions? I'll give you a simple example.\[\rm 2Mg + O_2 \to 2MgO\]This means that for every two moles of Mg and every one mole of O, you get two moles of MgO.

OpenStudy (anonymous):

OK...

OpenStudy (anonymous):

So in our reaction, can you think of the number of moles of \(\rm H_2\) using the same logic?

OpenStudy (anonymous):

ummm.....one....?

OpenStudy (anonymous):

it can't be more than 3 can it?

OpenStudy (anonymous):

so it has to be either one or two...I would imagine.. my brain does not want to process this...work, dammit, WORKK!!

OpenStudy (anonymous):

\[\rm Mg + 2HCl \to MgCl_2+H_2\]If you have one mole of magnesium and two moles of hydrochloric acid, you're gonna get one mole of \(\rm MgCl_2\) and one mole of \(\rm H_2\). Do you understand why that is?

OpenStudy (anonymous):

well...kinda...I would have expected that you'd get 2 moles of MgCI2 though...

OpenStudy (anonymous):

Here is how I understood this: First, clear your mind. Second, think about this carefully: If one molecule of Mg reacts with two molecules of HCl, then you would get one molecule of \(\rm MgCl_2\) and one molecule of \(\rm H_2\). Do you agree with the above to start with?

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