Calculate the period (T) of uniform circular motion if the velocity is 40.0 m/s and centripetal acceleration is 20.0 m/s2.

Question

anonymous · Answer

@YanaSidlinskiy

yanasidlinskiy · Answer

Centripetal acceleration, a= v^2/r 
This gives r = v^2/a = 40.0^2/20.0 = 80.0m 
Angular velocity, w = 2pi/T. Also w = v/r. 
So 2pi/T = v/R 
2pi/T = 40.0/80.0 = 0.5 
T = 2pi/0.5 = 12.6s

anonymous · Answer

A bit confusing but i understand it a little more thank you

yanasidlinskiy · Answer

What's confusing?

anonymous · Answer

Just the process of getting to it

yanasidlinskiy · Answer

Notice, That I have seperated them. One is Centripetal acceleration and the other one is Angular velocity. To get to the answer, we would add.

anonymous · Answer

Okay okay it makes more sense now

yanasidlinskiy · Answer

:D

anonymous · Answer

Thanks for helping your awesome :D

yanasidlinskiy · Answer

Your Welcome:D I wouldn't say I am though..