Question

Calculate the period (T) of uniform circular motion if the velocity is 40.0 m/s and centripetal acceleration is 20.0 m/s2.

Answer 1

@YanaSidlinskiy

Answer 2

Centripetal acceleration, a= v^2/r
This gives r = v^2/a = 40.0^2/20.0 = 80.0m
Angular velocity, w = 2pi/T. Also w = v/r.
So 2pi/T = v/R
2pi/T = 40.0/80.0 = 0.5
T = 2pi/0.5 = 12.6s

Answer 3

A bit confusing but i understand it a little more thank you

Answer 4

What's confusing?

Answer 5

Just the process of getting to it

Answer 6

Notice, That I have seperated them. One is Centripetal acceleration and the other one is Angular velocity. To get to the answer, we would add.

Answer 7

Okay okay it makes more sense now

Answer 8

:D

Answer 9

Thanks for helping your awesome :D

Answer 10

Your Welcome:D I wouldn't say I am though..