Question

Calculate the velocity of a 1650 kg satellite that is in a circular orbit of 4.2 x 106m above the surface of a planet, which has a radius 3.95 x 105 m and the period of the orbit is 2.0 hours.

Answer 1

@YanaSidlinskiy one more..? this one has killed me for the last 2 days

Answer 2

@chmvijay

Answer 3

Ok. Sorry. I made you wait..

Answer 4

No its fine

Answer 5

if a satellite is moving in a orbit of radius R with velocity V and time period T then
its time period is given by

\(T=\huge\frac{ 2\pi R }{ V}\)
so velocity will be
\[V = \frac{ 2\pi R }{ T }\]

Answer 6

What did you get?

Answer 7

So 2*pi*3.95*10^5/2

right?

Answer 8

I FINALLY GOT IT 1.24*10^6m/s

Answer 9

Please tell me thats right

Answer 10

Yep!:) You are correct! Sorry I had to run an errand..

Answer 11

Its fine and thank you sooooooooooo much!!!!!!

Answer 12

You're Welcome!! :D