Question

If 279 grams of iron react with an excess of oxygen, as shown in the balanced equation below, how many grams of iron (III) oxide can be formed?

4Fe + 3O2 2Fe2O3

Answer 1

@Abmon98

Answer 2

Number of Moles=Mass(g)/Molar Mass(g/mol)
279/56=4.98 moles of iron
Look for the ratio of moles of iron to iron oxide which is 4:2
4.98*2/4=2.49 moles
2.49=Mass/159
Mass=2.49*156=369.0grams

Answer 3

You mean399?

Answer 4

sorry the answer is 395.91

Answer 5

139.5 grams

199.5 grams

399 grams

1596 grams
No?.. It has to be 399

Answer 6

(279/56)*2/4*159.69=397.799 grams

Answer 7

.-. So 399 still.... Because that's the only one that fits