If 279 grams of iron react with an excess of oxygen, as shown in the balanced equation below, how many grams of iron (III) oxide can be formed?

4Fe + 3O2 2Fe2O3

Question

If 279 grams of iron react with an excess of oxygen, as shown in the balanced equation below, how many grams of iron (III) oxide can be formed?

4Fe + 3O2  2Fe2O3

lovelyharmonics · Answer

@Abmon98

abmon98 · Answer

Number of Moles=Mass(g)/Molar Mass(g/mol)
279/56=4.98 moles of iron
Look for the ratio of moles of iron to iron oxide which is 4:2
4.98*2/4=2.49 moles 
2.49=Mass/159
Mass=2.49*156=369.0grams

lovelyharmonics · Answer

You mean399?

abmon98 · Answer

sorry the answer is 395.91

lovelyharmonics · Answer

139.5 grams

 199.5 grams

 399 grams

 1596 grams
No?.. It has to be 399

abmon98 · Answer

(279/56)*2/4*159.69=397.799 grams

lovelyharmonics · Answer

.-. So 399 still.... Because that's the only one that fits