explain the difference between using the trigonometric ratios (sin,cos,tan) to solve for a missing angle in a right triangle versus using the reciprocal ratios (sec,csc,cot). you must use complete sentences and any evidence needed (such as example) to prove your point of view.

Question

anonymous · Answer

medal will be given

anonymous · Answer

@Hero

anonymous · Answer

@jdoe0001

anonymous · Answer

@jdoe0001 please help me

anonymous · Answer

medal will be given!!! help someone

anonymous · Answer

@ParthKohli

anonymous · Answer

@Luigi0210 please help me

anonymous · Answer

@jdoe0001 please help me please

anonymous · Answer

I SERIOUSLY NEED HELP PLEASEEEEEEEEEEEE @Luigi0210

anonymous · Answer

@dan815 hi can you help me

anonymous · Answer

@wio can you please help me?

anonymous · Answer

medal will be given

anonymous · Answer

can someone help

anonymous · Answer

well $$
\sin = opposite/hypotenuse
$$But $$
\csc = hypotenuse / opposite
$$

anonymous · Answer

So you can use $$
hypotenuse \times \sin = opposite
$$if you want to find the opposite side length and have hypotenuse.  You can use $$
opposite \times \csc = hypotenuse
$$If you want to find the hypotenuse and have the opposite side.

anonymous · Answer

but what is the difference of the two when you want to find an angle

anonymous · Answer

and in a right triangle

anonymous · Answer

in that case, it doesn't really matter.

anonymous · Answer

ok.. so the explaination that you gave me was to find an angle right?

anonymous · Answer

we dont have to find a side we have to find a missing angle.... @wio

anonymous · Answer

@jdoe0001 i need help

anonymous · Answer

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anonymous · Answer

@thomaster please help

anonymous · Answer

@IMStuck hi can you pleae help me

imstuck · Answer

Oh, I will definitely try.  Let me do some dwelling first...

anonymous · Answer

ok thankyou @IMStuck just please dont forget to come back

imstuck · Answer

When you use the trig functions as opposed to their cofunctions, there are no fractions involved.  When you use cofunctions, such as sec, csc, and cot, you are involving fractions.  For example, in this triangle|dw:1403657147415:dw|

imstuck · Answer

So to find the sin of an angle using csc, you have to take the reciprocal of the result.  It is the same with all the functions and their cofunctions.  They are reciprocals.

anonymous · Answer

ok thank you so much!!!

imstuck · Answer

Does that help you in your endeavors to answer this correctly?

anonymous · Answer

yes it does unless you have something else to say

anonymous · Answer

wait does it turn into a negative @IMStuck

imstuck · Answer

no.  They are not opposite reciprocals, only reciprocals.

anonymous · Answer

ok thank you so much

imstuck · Answer

You're very welcome!