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Mathematics 20 Online
OpenStudy (anonymous):

1.What is the average common ratio between the successive height values of ball 1? Ball 2? Ball 3? Experimental errors may cause common ratios to have some variances within the data for one ball. Use the average common ratio.

OpenStudy (anonymous):

OpenStudy (imstuck):

Let me check it out, ok?

OpenStudy (anonymous):

ok :)

OpenStudy (imstuck):

For the first one, you need to decide "what do I have to do to the 3 to get to the 2.4? Then what do I have to do to the 2.4 to get to the 1.9?" What I did to come up with answer was divide the 3 by 2.4. I came up with 1.25. So I decided to see if, when I divide each term by 1.25, will I get the next term in line? I did. 3/1.25 = 2.4. 2.4/1.25= 1.9. 1.9/1.25 = 1.5. So the common ratio for ball 1 is 1.25

OpenStudy (imstuck):

1.58 is ball 2's common ratio. I found that the same way. See, the common ratio is only a reflection of the change in the data. The change from one point to the next is to divide it by 1.58.

OpenStudy (imstuck):

Ball 3 is not working out like the rest.

OpenStudy (imstuck):

Here's from you problem above: Experimental errors may cause common ratios to have some variances within the data for one ball. This must be that ball!

OpenStudy (imstuck):

*your

OpenStudy (imstuck):

The average common ratio would be to add the 2 ratios you found and divide them by 2. That's the average common ratio.

OpenStudy (anonymous):

wait what? sorry I was at dinner

OpenStudy (anonymous):

@IMStuck

OpenStudy (anonymous):

Help @IMStuck @radar I need help with this problem to as well

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