Question

Find the solution of 2x^3-3x^2-11x+6(Use synthetic division)

Answer 1

Is my answer correct? f(x):{-2,1/2,3}

Answer 2

what is your divisor?

Answer 3

what do you mean?

Answer 4

\(2x^3-3x^2-11x+6\) does not have anything dividing it...

Answer 5

no, it doesn't

Answer 6

Exactly. That is what nconley meant. You are asking to check a division, but not what is dividing that.

Answer 7

so would i factor it

Answer 8

Well, one way to find an answer is to use synthetic division. But you need to know what is input to do it. So you need to know what values of x are being tested.

Answer 9

\[what?\div2x^3-3x^2-11x+6\]

Answer 10

would the values be (2x-1)(x+2)(x-3)

Answer 11

"Find the solution of 2x^3-3x^2-11x+6(Use synthetic division) " is an incomplete question. You need one of two things. 1) Something to divide it by. 2) Inputs you want answers for.

Factors are not a solution.

Answer 12

yes its divisor should be a 2nd degree polynomial

Answer 13

recheck your question

Answer 14

Have you been studying the Remainder Theorem?

Answer 15

I doubled checked the question and it's right

Answer 16

the way i wrote it

Answer 17

OK, then you said "Is my answer correct? f(x):{-2,1/2,3}"

Is that really uoir answer or is that part of the question?

Answer 18

@e.mccormick yes i have studied it annd that's my answer

Answer 19

Well, the question as asked does not have that as an answer. Something is missing.

Answer 20

That's what i thought too and I'm going to ask my prof. lol
I'll get to you in a bit

Answer 21

use guess and check to get 2 as a solution

Answer 22

the use long division to factor into (x-2)(2x^2-7x+3)

Answer 23

solve the quadratic

Answer 24

err -2 as a solution...

Answer 25

-2 was not given to him. -2, 1/2, and 3 are the roots he found.

Answer 26

yes, many times when given a 3rd degree polynomial , we guess the first solution, then use that to find the others

Answer 27

if 1,-1,2,-2,3,-3 dont work, I use that Italian dudes method.

Answer 28

I forgot his name...

Answer 29

so my answer is wrong

Answer 30

I dont know, I never checked the zeros of the quadratic ...

Answer 31

@zzr0ck3r why did you use -2

Answer 32

because it is a solution

Answer 33

@zzr0ck3r There is nothing given to solve. The question does not say, "Find the roots..." it says "Find the solution..." and states "...(Use synthetic division)" When you use synthetic division to find a solution you are using the Remainder Theorem . To use that, you must be given a list of x values. They have not been given x values to test.

The values you are testing are ones Mira made. Not ones they were given.

Answer 34

I tried 1, nope
I tried 2 nope
I tried -1, nope
I tried -2 BINGO

Answer 35

well I am used to poorly worded questions, but surly that is what it means....

Answer 36

again I tried 1, then 2, then -1, then -2
-2 worked. then we are done

Answer 37

I give these questions to students all the time,

Answer 38

there is NO other way to find the roots without the Italians algorithm or some other super fancy math....

Answer 39

So I assume that it is solvable with the information given, and sure enough it is...

Answer 40

It does not say to find roots. It says to find a solution. If it is not =0, then roots are not the solution.

Answer 41

obviously it means find the roots

Answer 42

this is a common mistake, asking for solution to polynomial when they mean root of polynomial or solution to the homogenous equation

Answer 43

Not if the person has been studying the Remainder Theorem. There can simply be a list of test points that has been missed. Making an assumption about the intent of the question can assure that they get it wrong. It is far better to have the student ask which information is missing.

Answer 44

again, I am assuming everything I see as obvious is correct, if it is we can find the answer. if not its jibberish

Answer 45

like you said, without my assumptions the question does not make sense, so I assume it does make sense....I am done with this conversation. I dont need any life lessons....lol this is not number theory ( I am guessing). Again. This method is fairly common, and im sticking to my answer.

Answer 46

there is not typo in this problem

Answer 47

what class is it for?

Answer 48

algebra

Answer 49

then use my method and ignore our discussion

Answer 50

college algebra

Answer 51

there is a type in the question, solution makes no sense without an equation, and you have no equation

Answer 52

slright @zzr0ck3r
so i would use x-2

Answer 53

typeo

Answer 54

yes divide by (x-2) to get the polynomial to factor into one linear factor and one quadratic.

Answer 55

the solve the quadratic

Answer 56

and by solve I mean find the roots....

Answer 57

which you got (x-2)(2x^2-7x+3)

Answer 58

correct, I showed the work on how to do that in my attachment...

Answer 59

so then that would be my answer?

Answer 60

Tanya u help?

Answer 61

e.mccormick has helped her already i guess.

Answer 62

i'm still confused

Answer 63

can you follow my attachment that says how to factor it into

\((x-2)(2x^2-7x+3)
\)

?

Answer 64

where did you get (2x^2-7x+3)?

Answer 65

@zzr0ck3r

Answer 66

do you see the file I attached?

Answer 67

yes

Answer 68

this is long division of polynomials.

Answer 69

if you cant follow those steps, I suggest you google it. That would be faster than me trying to explain(because of the horrible notation).

Answer 70

google "synthetic division of polynomials"

it is very easy.

Answer 71

i asked my teacher and he said this
There is no part missing, you have to try with a couple of numbers (divior of a_0/a_n)