The polynomial x^3 + 5x^2 -57x -189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. If the width of the box is 15 in., what are the other two dimensions? ( Hint: The height is greater than the depth.) A. height: 19 in. depth: 5 in. B. height: 21 in. depth: 5 in. C. height: 19 in. depth: 7 in. D. height: 21 in. depth: 7 in.
I assume you've done factoring of quadratics?
Nope..but i havet cause idk what that is lol
well... you may want to ... cover that first I'd think
quadratic == equation of 2nd degree
hint: \(\bf x^3 + 5x^2 -57x -189 \div (x+3)\to (ax^2+bx+c)\to (x+\square )(x+\square )\)
What are the value's of a,b and c? /.\
i divided as he said and got x^2+2x-63
so a=1 b=2 and c = -63
idk what to do after that with his equation
as I said, you may want to cover your quadratics section first
okay how do you do that?
When you have the quadratic equation you can go about it by using the quadratic formula or by decomposing it by factoring the quadratic into two different values of X as jdoe0001 has shown above
It requires the understanding of quadratics, show your work and someone will gladly guide you towards the proper solution. No better way to learn by than from your own mistakes.
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