What is the possible discriminant of the graph?
-15 zero 17 25
ok
discriminant is b^2-4(a)(c) (when looking at ax^2+bx+c)
but i am not given the equation itself
yes, but are given the graph of t. Write the equation from the graph and do it.
how do i write it when i am only given the points
help me
well to narrow down your answer choices a bit, the discriminant would have to be positive. if the discriminant of a quadratic is negative, then only imaginary solutions exist. If the discriminant is 0, then there is only one real solution. If the discriminant is positive, then there are 2 real solutions. Since your graph crosses the x axis twice there are two real solutions and therefore the discriminant must be positive
-15 zero 17 25
these are the ptions
and i just got rid of two of them ;)
yup
now what about last 2
i think we need to find the discriminant discriminant is b^2-4(a)(c) (when looking at ax^2+bx+c) but i dont know how bring it in this form
well, its a little tough because they give you very ugly roots as points... but from those roots, you can solve for the equation of the quadrative. y=0 when x =-4.56... and when x=-.438 so if you wanted to, you could say 0 = (x+4.56...)*(x+.438...) and simplify. thats assuming your A term is 1, though its a bit hard to tell from that graph
its 17 i got it thanks for the help
No problem :)
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