Question

A ball is thrown upward from the top of a building. The function below shows the height of the ball above the ground, ft, in feet, at different times t in seconds:

f(t) = -16t^2 + 32t + 90

The average rate of change of f(t) from t = 4 to t = 6 is _____.

Answer 1

@SithsAndGiggles @zepdrix

Answer 2

Average rate of change is
\[ROC=\frac{f(x_2)-f(x_1)}{x_2-x_1}\]

Does this help?

Answer 3

so do i basically just do this. \[\frac{f(4)-f(6)}{ 4-6 }\]

Answer 4

Not exactly, the x_2 value is the second time value:

\[\frac{f(6)-f(4)}{6-4}\]

Otherwise you would get a value negative of the answer