Question

How much MnO2(s) should be added to excess HCl(aq) to obtain 295 mL of Cl2(g) at 25 °C and 755 Torr?

Answer 1

start by finding how many moles of \(Cl_2\) you want. Use the ideal gas law, PV=nRT.

Answer 2

don't forget to convert units to needed units
Pressure= to Pascals
Volume= to m3
Temperature= to Kelvin
R- is constant which is = 8.31
and n is mole

Answer 3

MnO2 + 4 HCl -> MnCl2 + 2 H2O + Cl2

this is the reaction
after finding mole of Cl2 look at the ratio between MnO2 and Cl2
(look at the coefficients meaning numbers before the element/compound, if there are no numbers before the compound that means the coefficient is 1 )
so here we can see that the ratio is 1 to 1 so that means MnO2 moles are same as Cl2 moles

most probably 'by how much of MnO2' they mean mass @aaronq ?

if so then you have mole and you can find molecular mass from periodic table
so use formula of mole
mole= mass/Molecular mass
so mass= mole*molecular mass
and get the answer :D

hope it helps :)

Answer 4

yeahhh, grams probably.

Answer 5

thnx @aaronq ♥