find solution set to t−3t+6−−−−−√=−2
\[t-\sqrt{3t+6} = -2\]
you want to fin the value of t?
yes both solutions
ok... first transpose -square root of 3t + 6 to the right side, and transpose -2 to the left soit gives you a new equation that are easy to handle... its t + 2 = square root of 3t+6...
#1 Consider the Domain \(3t+6 \ge 0\) #2 Isolate the radical on one side. Why are we posting the same question twice?
raise both sides of the equation to the power of to to ditch the radical sign...
power of 2 rather
can someone draw this out or type the equation so i can get a visual picture
Did you do Step #2? #2 Isolate the radical on one side. Do that, and you will have a visual picture.
t+2 = \[\sqrt{3t+6}\]
@retep If you use parentheses () rather than brackets [], that won't happen. :-)
@retep then I square both sides?
yes
when you expand the left side (t+2)^2 ..it gives you t^2 + 4t + 4, and the right side, when you raise it in the 2nd power the square root will be eliminated and it gives you a 3t + 6 only... got already
?
ok i figured it out thank you
YW
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