help please !! will give medal and fan
@campbell_st @zepdrix @elle150
Have you learned that the exponent 1/2 means the square root?
For example, \(\large a^{\frac{1}{2}} = \sqrt{a} \)
For example \(\large 25^{\frac{1}{2}} = \sqrt{25} = 5\)
yeah
since the solid is a square just take the square root \[\sqrt{64n^{36} }= \sqrt{64} \times \sqrt{n^{36}}\] then apply a little index notation for the square root \[\sqrt{64} \times (n^{36})^{\frac{1}{2}}\] hope it helps
The area of a square is the square of the side. The side of a square is the square root of the area.
ohhhh
i love how you explain @mathstudent55
lol...someone always gives an answer
That means since you have the area, you need to take its square root to find the side.
yep
And sometimes it isn't always the right answer
i know
lol
Please don't just shout answers (wrong or right) in the future @elle150 . Thanks kindly.
i dont mind
@karendiaz123 Answers (in this case) can be misleading as it might not be the right answer.
oh true i understand
\(Area = 64n^{36}\) \(\large Side = \sqrt{Area} = \sqrt{64n^{36}} = \sqrt{64}\times \sqrt{n^{36}}\) \(\large = (8^2)^\frac{1}{2} \times (n^{36})^{\frac{1}{2}}\) Now apply the rule of raising an exponent to an exponent.
Also it doesn't help the asker to just have an answer. For example, in this case if you did go with that choice, it would be nice that you could actually confirm that was the right answer. But you wouldn't be able to unless you knew how to get there. And if you knew how to get there yourself then you could definitely eliminate that answer as a choice.
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