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Mathematics 23 Online
OpenStudy (eric_d):

Topic: Exponential & Logarithmic functions Sketch the graph of

OpenStudy (eric_d):

\[a) y=2^{x}\]

OpenStudy (anonymous):

sorry not really that good at math :/

OpenStudy (eric_d):

@ARMYRANGERS

OpenStudy (anonymous):

|dw:1403707070412:dw|

OpenStudy (eric_d):

Can u teach me how to sketch such graph Is there any formula

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

If you want to qualitatively just check nature of the function

OpenStudy (anonymous):

So here you see as you increase x, y is also increased. At x = - infinite y goes to zero. At x = 0, y is 1 and at x = + infinite, y also goes to infinite.

OpenStudy (anonymous):

If the function may have local minima or maxima, you also need slope of this function at some points to plot it.

OpenStudy (anonymous):

Does that help ?

OpenStudy (eric_d):

yes nxt question: y=-2^x

OpenStudy (anonymous):

If I put x = 0 what will be y ?

OpenStudy (eric_d):

-1

OpenStudy (eric_d):

I know hw to sketch that

OpenStudy (anonymous):

Great! Now check if the function is ever increasing or decreasing ?

OpenStudy (eric_d):

decreasing

OpenStudy (anonymous):

What if x =+ infinite and x = -infinite ?

OpenStudy (eric_d):

I'm nt sure. Can u explain..

OpenStudy (eric_d):

it goes down is it so

OpenStudy (anonymous):

When x = + infinite, y = - infinite

OpenStudy (anonymous):

When x = - infinite, y goes to -0. Right ?

OpenStudy (eric_d):

I think it will be easier for me to understand if u sketch...

OpenStudy (anonymous):

Can you show what you think it should be? If you don't get it write, I'll draw it for you.

OpenStudy (anonymous):

@eric_d ?

OpenStudy (eric_d):

when x= - infinite, y can be positive too rite

OpenStudy (anonymous):

Nope! It is -2^x ! If x goes to -infinite, 2^x will go to zero, so -2^x will go to -0. That means y will never cross 0. It will always be less than 0.

OpenStudy (eric_d):

okay

OpenStudy (eric_d):

There are a few more question Can u help me...

OpenStudy (anonymous):

Show me the graph. Then we'll move to next question. :)

OpenStudy (eric_d):

ok

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