Ill Give Medals
Nellie is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?
x g(x)
1 5
2 10
3 15
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OpenStudy (anonymous):
Yes, at positive x-coordinates
Yes, at negative x-coordinates
Yes, at negative and positive x-coordinates
No, they will not intersect
OpenStudy (anonymous):
OpenStudy (anonymous):
@Hotchellerae21
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i need i dont know this stuff and i cant find it in my lesson
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OpenStudy (anonymous):
I need Help
OpenStudy (anonymous):
I think you should try plotting the graph of g(x) and if there's a point that will pass through the graph of f(x), then they have an intersection.
OpenStudy (anonymous):
i did and i think its B
OpenStudy (anonymous):
@Data_LG2
OpenStudy (anonymous):
gimme a sec. i'll take a look
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Its either C or B
OpenStudy (anonymous):
hello @Data_LG2
OpenStudy (anonymous):
Can you help @CynfulBaddie
OpenStudy (anonymous):
@Data_LG2
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OpenStudy (anonymous):
can you help @Hotchellerae21
OpenStudy (anonymous):
i can try
OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
hello i think its C now looking at the problem @Hotchellerae21 @Data_LG2
OpenStudy (anonymous):
i think it is C too i don't know
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OpenStudy (anonymous):
it could also Be B
OpenStudy (anonymous):
can you help me @amistre64
OpenStudy (anonymous):
@Hotchellerae21
OpenStudy (anonymous):
@data
OpenStudy (anonymous):
@Data_LG2
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OpenStudy (anonymous):
ill give you all medals
OpenStudy (anonymous):
If you help
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
yes what?
OpenStudy (anonymous):
@dan815
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OpenStudy (anonymous):
Can you help @dan815
OpenStudy (dan815):
Figure out what the equation of that quadratic function is
OpenStudy (anonymous):
thanks @dan815
OpenStudy (anonymous):
i pretty sure its B
OpenStudy (anonymous):
@dan815
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OpenStudy (dan815):
y=ax^2+bx+c
are x=0, y=2 so
2=a(0^2)+b(0)+c
therefore c=2
y=ax^2+bx+2
Now, sub in another couple points
4=a(2^2)+b(2)+2
4=a(-2)^2+b(-2)+2
----------------
4=4a+2b+2
4=4a-2b+2
-------------
^---- solving these 2 equations gives us
a=1/2 and b=0
y=1/2x^2+2 <-- is our equation
OpenStudy (anonymous):
so is it B Because im pretty sure it is
OpenStudy (anonymous):
@dan815 is it B
OpenStudy (dan815):
y=mx+b is the equation of a line, i want to rush a bit so
y=5x is the eqn of your line
lets see if theres an intersection
y=5x
y=1/2x^2+2
5x=1/2x^2+2
10x=x^2+4
x^2-10x+4=0
\[+or-b+\frac{\sqrt{(b^2-4ac)}}{2a}\]
under the radical b^2-4ac= 100-(4*1*4) <--- isnon negative so, yes there will be intersection points, infact 2 intersection points