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Chemistry 7 Online
OpenStudy (anonymous):

In 75.0 g of an aqueous solution that is 6.8% AgNO3 by mass, how many grams of solvent are present?

OpenStudy (anonymous):

6.8%/100=0.068 75*0.068=5.10g AgNO3 75-5.10=69.9g Solvent

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