@TuringTest
I'm debating between b and c.
f[g(10)] is undefined, which means that f is undefined for whatever value g(10) is but we know for what value f(x) is undefined, so that value must be g(10) make any sense?
yes, b.
no, sorry let me give a quick explanation why b is wrong
we are told that the domain of f is all x except x=3, so f(10) must be defined... only f(3) is undefined
*but*, if f(3) is undefined, and f[g(10)] is undefined, what must g(10) be?
since it doesn't =3 it must be "D".
again, no, because it says 'the domain of g is all real numbers' that means that g(x) is always defined
when you say 'it' doesn't equal 3, what do you mean?
b/c 3 is undefined it can not be any of the answers that say =3
3 is just number; it can't be undefined but the *function* f(x) is undefined at x=3 the function g(x) is defined everywhere
f(x) could =3 for some x like 5, or -649, or whatever, so saying that all the '=3's must be wrong is not correct
f(x) is only undefined for one number: 3 we are told that f( *something* ) is undefined, and then we are told that 'something' is g(10) that means g(10) can only be one thing...
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