Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Finding Median of a trapezoid Please Help: Question in comments! I know the answer is 4 but I dont know how to solve these equations.

OpenStudy (anonymous):

OpenStudy (mathstudent55):

The length of the median is the average of the lengths of the 2 bases. In other words, to find the length of the median, add the lengths of the 2 bases and divide by 2.

OpenStudy (anonymous):

I understand that part. I am having problems with the substitution where you have to add the 2 equations together

OpenStudy (mathstudent55):

Think of the expressions for the 2 bases as numbers. Let's call them A and B. If you need to find the average of A and B, you simply do this: \(\dfrac{A + B}{2} = ~average\) You know the average is 23. Also, for you, A = 8x + 3, and B = 3x - 1. Substitute those values for A, B, and "average" in the expression above. Then solve for x.

OpenStudy (anonymous):

I understand that part. I'm having problems with substitution. Do you think you could help me with that?

OpenStudy (mathstudent55):

Ok, let's set up the equation with x. Add the bases: (8x + 3) + (3x - 1) Ok so far?

OpenStudy (anonymous):

Or I guess adding the 2 equations together I should say...

OpenStudy (anonymous):

Ok I have my paper ready that looks good so far

OpenStudy (mathstudent55):

Since we are finding the average of the lengths of the bases, after we add them, we divide them by 2. \(\dfrac{(8x + 3)+(3x - 1)}{2} \) Ok, so far?

OpenStudy (anonymous):

yes

OpenStudy (mathstudent55):

The figure shows us that the median has a length of 23. Our expression is the length of the median, so our expression must be equal to 23. \(\dfrac{(8x + 3)+(3x - 1)}{2} = 23\) This is the equation that has to be solved to x.

OpenStudy (anonymous):

how do you add the 2 equations together is what Im wondering

OpenStudy (mathstudent55):

First, remove the parentheses because in this case, they're unnecessary. \(\dfrac{8x + 3+3x - 1}{2} = 23\) Now you add like terms. Like terms are terms that have the same variable part. The variables are the letters. In our case our variable is x. You add 8x to 3x, and you subtract 3 - 1. That goes in the numerator.

OpenStudy (anonymous):

ok so now I have 5x + 2 =23 And I subtract the 2 from 23?

OpenStudy (anonymous):

11x*

OpenStudy (mathstudent55):

BTW, they are not equations. An equation is a statement that "equates" two things. An equation is a statement with an equal sign. These are simply expressions.

OpenStudy (mathstudent55):

Wait. Don't forget the denominator.

OpenStudy (anonymous):

ok thanks for clarifying Not that I have enough to worry about :) haha

OpenStudy (mathstudent55):

This is what you have now. \(\dfrac{11x + 2}{2} = 23\)

OpenStudy (anonymous):

Yes that is what i have

OpenStudy (mathstudent55):

Now we multiply both sides by 2 to get rid of the denominator of 2 on the left side. \(\dfrac{11x + 2}{2} \times 2= 23 \times 2\) \(11x + 2 = 46\)

OpenStudy (mathstudent55):

Now you subtract 2 from both sides.

OpenStudy (anonymous):

Oh I see. OK let me solve that hld on

OpenStudy (anonymous):

I will give you the steps and you tell me if their right?

OpenStudy (anonymous):

\[11x + 2 =46 \]

OpenStudy (anonymous):

11x = 44 x =4

OpenStudy (anonymous):

Thank you so much! I really appreciate it!

OpenStudy (anonymous):

is there a way I can rate you?

OpenStudy (mathstudent55):

This is how it should look: 11x + 2 = 46 11x = 44 (subtracting 2 from both sides) x = 4 (dividing both sides by 4)

OpenStudy (mathstudent55):

You can click on "Best Response" to give me a medal if you'd like to.

OpenStudy (anonymous):

May I ask if you are in college or what school you attend?

OpenStudy (anonymous):

What college did you attend if you dont mind me asking?

OpenStudy (anonymous):

Lovely, Im only a sophomore in HS but I plan on attending Embry Riddle in Daytona Beach. Im sure you have heard of that school.

OpenStudy (anonymous):

I live right near Boca Raton acually lol

OpenStudy (anonymous):

yes

OpenStudy (mathstudent55):

Great. Keep studying and asking questions. That's how you learn. Also, in math, solving tons of practice problems helps a lot.

OpenStudy (anonymous):

Thanks for the help, I would love to give you a medal how do i do that?

OpenStudy (mathstudent55):

Click on "Best Response" in one of my answers.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!