@ParthKohli Hi, could i please get some help with substitution?
5x-y=6 2x+y=8
Hey, do you have to solve this using substitution?
yes i did but i kind of did something wrong when i graph it i got (2,4) when i did with substitution i did not get the same.
How did you do it?
I kind of flip it to make it easier so i did 2(6-5x)+y=8 and solve and check in the end do i really need to everything i did
Hmm, I believe you've made the wrong substitution.
Could you please help me with it?
Sure. So you want to find \(x\) from the first equation and place it into the second.\[5x - y = 6\]First, you would take \(y\) to the other side.\[5x = y + 6\]Then you would divide both sides by \(5\) to get \(x\) alone.\[x = \dfrac{y + 6}{5}\]Do you follow?
Yes...
Can you place this value of \(x\) into the second equation now?
I do not know how put it i only know when it is not with division
Alright, if you want it that way, we're gonna change our ways. We're gonna find the value of \(y\) from the second equation and we're gonna place it into the first.
Ok..
so how do you do it
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