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Mathematics 14 Online
OpenStudy (anonymous):

@Johnbc I'm confused

OpenStudy (anonymous):

Hello Lilia222

OpenStudy (anonymous):

I have set up the following equation 4x=25+4x I'm a bit confused...

OpenStudy (anonymous):

Area of a rectangle A = length x width

OpenStudy (anonymous):

the length is 4 more than-> 4(w) the area is 25 more than-> 4(w)

OpenStudy (anonymous):

Length of a rectangle is 4 "more" than its width. 4+L = W

OpenStudy (anonymous):

Area of a rectangle is 25 "more" than 4 "times" the width A = 25 + 4W

OpenStudy (anonymous):

You know have a value for the Width and Area. So if you re-arrange the Width formula you can find a formula for the Length. \[4 + L = W\] \[L = W - 4\]

OpenStudy (anonymous):

Using the formula \[Area = L \times W\] Plug in what you know and solve for what you do not know

OpenStudy (anonymous):

that's impossible there is not another number

OpenStudy (anonymous):

A = l x w

OpenStudy (anonymous):

25+4W = (W-4) x (W) Solve for W?

OpenStudy (anonymous):

10.40

OpenStudy (anonymous):

10.40 = w the length is 4 more than 10.40-> 14.4 the area is 25 more than 10.40-> 35.4

OpenStudy (anonymous):

no area is 66.6

OpenStudy (anonymous):

\[25 + 4W = (W-4) \times W\] \[25 - 4W = W^2-4W\] If we add 4W to both sides we get\[25 = W^2\]

OpenStudy (anonymous):

It is asking for the Width (W) not the area?

OpenStudy (anonymous):

You must now solve for W to find your answer.

OpenStudy (anonymous):

Using the "opposite" operation of squared and doing it to both sides.

OpenStudy (anonymous):

5 :)

OpenStudy (anonymous):

Correct! Great job.

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

Always my pleasure Lilia222.

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