@Johnbc I'm confused
Hello Lilia222
I have set up the following equation 4x=25+4x I'm a bit confused...
Area of a rectangle A = length x width
the length is 4 more than-> 4(w) the area is 25 more than-> 4(w)
Length of a rectangle is 4 "more" than its width. 4+L = W
Area of a rectangle is 25 "more" than 4 "times" the width A = 25 + 4W
You know have a value for the Width and Area. So if you re-arrange the Width formula you can find a formula for the Length. \[4 + L = W\] \[L = W - 4\]
Using the formula \[Area = L \times W\] Plug in what you know and solve for what you do not know
that's impossible there is not another number
A = l x w
25+4W = (W-4) x (W) Solve for W?
10.40
10.40 = w the length is 4 more than 10.40-> 14.4 the area is 25 more than 10.40-> 35.4
no area is 66.6
\[25 + 4W = (W-4) \times W\] \[25 - 4W = W^2-4W\] If we add 4W to both sides we get\[25 = W^2\]
It is asking for the Width (W) not the area?
You must now solve for W to find your answer.
Using the "opposite" operation of squared and doing it to both sides.
5 :)
Correct! Great job.
thank you
Always my pleasure Lilia222.
Join our real-time social learning platform and learn together with your friends!