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Mathematics 8 Online
OpenStudy (anonymous):

Based on the data provided, which type of transaction is likely to bring in the most income during the next two-week transaction period?

OpenStudy (anonymous):

The table gives sales data for a stationery store in any given two weeks. It lists the probability of the number of items purchased in a single transaction and the average amount spent per transaction.

OpenStudy (anonymous):

a transaction with two items a transaction with three items a transaction with four items a transaction with five or more items

OpenStudy (anonymous):

Can anyone help? Please?

OpenStudy (anonymous):

Over some time you can see the one with the higher probability and higher cost will bring in the most, just by examination which do you think it is?

OpenStudy (anonymous):

I'm thinking it is a transaction with two terms.

OpenStudy (anonymous):

Well there are 2 transaction with high probability, 2 and 4 but which of those brings in more money?

OpenStudy (anonymous):

4?

OpenStudy (anonymous):

Correct it is very close to the probability of 2 and it brings in higher amount of income.

OpenStudy (anonymous):

So the answer is 4? Are you sure?

OpenStudy (anonymous):

Correct 4 and 2 will occur the most but 4 will bring in the most income.

OpenStudy (anonymous):

Omg! Thank you, do you mind helping me with one more?

OpenStudy (anonymous):

I can attempt!, yes.

OpenStudy (anonymous):

Based on the data provided, what is the probability that a patient treated under plan A will show remission?

OpenStudy (anonymous):

The possible answers are 0.55 0.40 0.75 0.60

OpenStudy (anonymous):

It says the patient will show remission rate at 40% for Doxo and it will show 25% for doce so 35% is not accounted for.

OpenStudy (anonymous):

Okay...I'm still kind of confused.

OpenStudy (anonymous):

Seems like 40% is the remission rate so as a probability out of 100 the remission rate stands as 40%/100%

OpenStudy (anonymous):

So it's 40%?

OpenStudy (anonymous):

You need to find the probability out of all possible possibilities so out of 100

OpenStudy (anonymous):

\[\frac{ 40 }{ 100 }\]

OpenStudy (anonymous):

40 divided by 100 is .4

OpenStudy (anonymous):

Correct, That is your probability out of all possibilities.

OpenStudy (anonymous):

So the answer is 0.40?

OpenStudy (anonymous):

Correct!

OpenStudy (anonymous):

that was wrong :c

OpenStudy (anonymous):

I must have made a mistake somewhere.

OpenStudy (anonymous):

If all the possibilities are just the 40% and 25% then our probability out of all possibilities would be 40%/65% = 0.615384 = 0.62

OpenStudy (anonymous):

Did not use that value because it had the 0.02 but they might have wanted a rounded answer?

OpenStudy (anonymous):

Rounded to the nearest tenth, you will have 0.60 when using that as the probability.

OpenStudy (anonymous):

Okay, I wrote that down. I probably need some more practice.

OpenStudy (anonymous):

Practice is a good idea.

OpenStudy (anonymous):

How about this one?

OpenStudy (anonymous):

We note that the prices are very similar so the one that occurs often should be the one to bring in the most income during the month.

OpenStudy (anonymous):

Yeah, that's what's really confusing me..

OpenStudy (anonymous):

Look at the one with the higher probability, it means it will occur most often.

OpenStudy (anonymous):

Is it 2?

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

Thank you! How about this one?

OpenStudy (anonymous):

Not entirely sure on that question.

OpenStudy (anonymous):

Uh oh...

OpenStudy (anonymous):

25% of the time the 825$ treatment works If not then the 1000$ treatment is next and works 40% of the time.

OpenStudy (anonymous):

Do you have an idea what it could be?

OpenStudy (anonymous):

No I am trying different ways but none seem to get me where I want to be.

OpenStudy (anonymous):

It's either A, B or C

OpenStudy (anonymous):

What are you currently studying?

OpenStudy (anonymous):

Prob and stats.

OpenStudy (anonymous):

@jcpd910

OpenStudy (anonymous):

Okay, not familiar with the formulas and rules for Probability and Statistics. It is asking per patient, if we assume a number of patients we might be able to find out the answer.

OpenStudy (anonymous):

Okay. Because I have no idea what the answer is.

OpenStudy (anonymous):

Yeah, I'm not familiar with this either. Maybe @dan815

OpenStudy (anonymous):

We know there are only 2 different treatments so a probability of 1 of our patients being under plan B is 0.5

OpenStudy (anonymous):

That's what I got but it's not one of the answers.

OpenStudy (anonymous):

Do you think it could be $850?

OpenStudy (anonymous):

There is a 25% chance that it works and its per patient so we are looking for an average

OpenStudy (anonymous):

I'm so confused...

OpenStudy (anonymous):

Out of all the patients. Plan B patients probability, \[\frac{ 0.25 }{ 0.65 } = 0.3846 \] Plan A probability \[\frac{ 0.40 }{ 0.65 } = 0.61538\] If we know that those who will only need the 850$ treatment is 0.3846 and those who will need the 850$ and 1000% treatment because the first will not work is 0.61538

OpenStudy (anonymous):

I just need a really good educated guess because I have to go to the next problem.

OpenStudy (anonymous):

So per patient I believe we will have, For those stopping at treatment 1, \[850 \times 0.3846 = 326.92\] For those needing further treatment, \[1850 \times 0.61538 = 1138.46\]

OpenStudy (anonymous):

Adding those up we get 1465.38

OpenStudy (anonymous):

Not sure but it looks closest to 1,510.

OpenStudy (anonymous):

Sorry I could not be of much help with this problem.

OpenStudy (anonymous):

It's okay, how about this one?

OpenStudy (anonymous):

OpenStudy (anonymous):

Not at all, sorry.

OpenStudy (anonymous):

Re-post the question so someone available and knows it might see it.

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