Russel throws a soda from the balcony of his house to his friend Jones in the pool. If the soda is released 20 feet from the ground, and is thrown with a downward velocity of 2 ft/s, how long till the soda hits the pool, ignoring air resitance?, where h is the height of the soda in feet and t is the time in seconds since Russel threw it. Round your answer to the nearest tenth. A. 0.5 seconds B. 0.8 seconds C. 1.1 second D. 1.6 seconds

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anonymous · Answer

c

anonymous · Answer

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anonymous · Answer

k np

tkhunny · Answer

Standard Setup.

$x(t) = -16t^{2} + V_{0}t + H_{0}$ describes the position of an object subject to only the force of gravity (ignoring air resistance).

We are given the initial velocity, $V_{0} = -2 ft/sec$
We are given the initial height, $H_{0} = 20 ft/sec$

Substitute these values and solve, $x(t) = 0$