Discrete Question: how would you prove that the product of a nonzero rational number and an irrational number is an irrational number?
Here is a hint: rational numbers are fractions like a/b with a and b integers, right?
yes
So rational/rational will be a rational number, right?
correct
So suppose we have a*b = c. With a and c rational. What kind of number must b be?
to get a rational it would need to be rational wouldn't it?
is rational closed under multiplication
Correct. So in our original problem ...c ... suppose for a moment we have a rational * irrational = possibly rational. But we know we cannot have that ... ... because rational * ______ = rational requires a rational in the blank.
Absolutely. Yes, it is closed.
so that would a good answer?
it is also closed under + - / except for division by zero.
If you note the proof by contradiction, then yes. (assume c is rational ... ... then b = c/a is rational ... but that violates our assumption that b is irrational)
ok, thanks!
You are welcome. This is a very powerful technique: assume the opposite of your conclusion ... ... and prove that nonsense results from that assumption. Things like "b is both rational and irrational", "1 = 0" and such are nonsense.
that is a good idea, I'll keep that in mind on the rest of these!
Great, good luck! :)
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