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Mathematics 8 Online
OpenStudy (anonymous):

Discrete Question: how would you prove that the product of a nonzero rational number and an irrational number is an irrational number?

Miracrown (miracrown):

Here is a hint: rational numbers are fractions like a/b with a and b integers, right?

OpenStudy (anonymous):

yes

Miracrown (miracrown):

So rational/rational will be a rational number, right?

OpenStudy (anonymous):

correct

Miracrown (miracrown):

So suppose we have a*b = c. With a and c rational. What kind of number must b be?

OpenStudy (anonymous):

to get a rational it would need to be rational wouldn't it?

OpenStudy (anonymous):

is rational closed under multiplication

Miracrown (miracrown):

Correct. So in our original problem ...c ... suppose for a moment we have a rational * irrational = possibly rational. But we know we cannot have that ... ... because rational * ______ = rational requires a rational in the blank.

Miracrown (miracrown):

Absolutely. Yes, it is closed.

OpenStudy (anonymous):

so that would a good answer?

Miracrown (miracrown):

it is also closed under + - / except for division by zero.

Miracrown (miracrown):

If you note the proof by contradiction, then yes. (assume c is rational ... ... then b = c/a is rational ... but that violates our assumption that b is irrational)

OpenStudy (anonymous):

ok, thanks!

Miracrown (miracrown):

You are welcome. This is a very powerful technique: assume the opposite of your conclusion ... ... and prove that nonsense results from that assumption. Things like "b is both rational and irrational", "1 = 0" and such are nonsense.

OpenStudy (anonymous):

that is a good idea, I'll keep that in mind on the rest of these!

Miracrown (miracrown):

Great, good luck! :)

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