A sample of an unknown solution is mixed with Ba (NO3)2 and a white phosphorous forms. The precipate does not redissolve in HNo3. When Na2CO3 is added to a fresh sample of the unknown solution, bubbles form and disappear into a clear solution. What compound does this solution contain?

Question

abmon98 · Answer

To test for a Sulphate anion we add few drops of Barium Nitrate, White precipitate is formed followed by Nitric acid No Change is observed

anonymous · Answer

How would you write that out?

abmon98 · Answer

Ba2+(aq) + SO42–(aq) ==> BaSO4(s)

anonymous · Answer

SO42? So four on the bottom, 2 on the top?

abmon98 · Answer

Thats an ionic equation the 2- and 2 are the charges of ion

anonymous · Answer

So on the Top right of each element? Thanks

abmon98 · Answer

Yes, Your welcome.

anonymous · Answer

The 4 on the top right of  the SO as well?

abmon98 · Answer

Do you have any options for your question, The SO42-(sulphate ion) the 4 represent the number of oxygen atoms present not the charge.