calculate the value of delta H for the combustion reaction CH3COOH(l) + 2O2 (g) = 2CO2 + 2H2O

CH3COOH = 487.0
CO2 = -393.5
H2O = -241.8

Question

calculate the value of delta H for the combustion reaction CH3COOH(l) + 2O2 (g) = 2CO2 + 2H2O

CH3COOH = 487.0
CO2 = -393.5
H2O = -241.8

aaronq · Answer

$\Delta H_{combustion}=\large \Sigma ~[\nu _iH^o_{f_i}(product)]-[\nu _iH^o_{f_i}(reactant)]$

anonymous · Answer

while the equation is helpful I actually need to know where to put the number...

aaronq · Answer

Can you identify the products and the reactants in the process you're analyzing?

The enthalpy of formation of each substance is multiplied by it's stoichiometric coefficient (denoted by $\nu$).