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Mathematics 14 Online
OpenStudy (anonymous):

I got this trig question. Find the unknown, show you solution

OpenStudy (anonymous):

|dw:1403786554791:dw| a=? b=? I don't know how to solve this and kindly please show the process. Thank you!

OpenStudy (anonymous):

You have a right triangle so you can apply the pythagorean theorem. \[A^2+B^2 = C^2\]

OpenStudy (vlery):

a= 5 b= 13

OpenStudy (anonymous):

okay.. but how.

OpenStudy (vlery):

first find A then find B using @Johnbc formula

OpenStudy (anonymous):

Use it to solve for C the hypotenuse for both triangles. Where C in the first triangle from left to right is "a" and for the second it is "b"

OpenStudy (anonymous):

okay. so meaning 4=A and 3=B then solve for A using pythagorean theorem. But how I know what side to put in the pythagorean. Any formula?

OpenStudy (anonymous):

It does not matter as long as C = Hypotenuse/Longest side

OpenStudy (anonymous):

oh I see! thank you very much now I fully understand ^.^

OpenStudy (anonymous):

|dw:1403786947782:dw| The way I like to look at my right angle triangles when using the pythagorean theorem.

OpenStudy (anonymous):

My pleasure.

OpenStudy (anonymous):

Gladly I found this site! So many helpful people

OpenStudy (anonymous):

wait! the square root of 12^2-5^2 should it be equal to 13 or 10.91. Because I'm unsure wether -(5)^2=25 or -(5)^2=-25. Which should come first? Exponent or the negative sign?

OpenStudy (vlery):

you add 5^2 and 12^2 because 5 is not the hypotenuse in the problem in finding B

OpenStudy (anonymous):

\[A^2+B^2=C^2\]

OpenStudy (anonymous):

So if we are solving for C, \[C = \sqrt{A^2+B^2}\] No subtraction.

OpenStudy (anonymous):

Yes I know. But what is -(5)^2?

OpenStudy (anonymous):

All of the sides are positive. Not sure where you got the negative sign?

OpenStudy (anonymous):

But I thought 12 is the hypotenuse.

OpenStudy (anonymous):

12 can not be the hypotenuse since it is one of the sides adjacent to the right angle.

OpenStudy (anonymous):

So you mean that the opposite of the right angle is always the hypotenuse?

OpenStudy (vlery):

the hypotenuse is the side where the right angel is facing it|dw:1403788121011:dw|

OpenStudy (anonymous):

|dw:1403788095060:dw|

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