Question

If the equation, C2H5OH (l) + 3O2 (g) arrow 2CO2 (g) + 3H2) (l), were performed in a laboratory at room temperature, both of the gas volumes: would depend on the surrounding temperature and pressure conditions
must always be equal because the molar ratios are the same
must always be equal because the number of representative particles is the same in the equation
could be calculated without regard to the temperature and pressure surrounding them

Answer 1

@Abhisar

Answer 2

I think it's the last one...

Answer 3

Since it's room temperature, they don't have to worry about the temp and pressure being exerted

Answer 4

Right?

Answer 5

Option is 1 is incorrect

Answer 6

It depends on the representative particles? :/

Answer 7

Option 3 is incorrect as volume depens upon temperature and pressure

Answer 8

PV=nRT

Answer 9

Wait..you know there are four options, right?

Answer 10

Oh LOL, option 1 is correct

Answer 11

Because Volume depends upon pressure and temperature according to combined gas law i.e PV=nRT

Answer 12

lmao
Ok...are you sure even though it's room temperature?

Answer 13

I feel like they called that out for a reason...or maybe they're trying to trip me up

Answer 14

Hmmm...must be one among a and c, lets cross check it with @Somy

Answer 15

ok

Answer 16

I have no idea who that is, but thanks for helping me out with this!
Science this year sucks :S

Answer 17

i don't even get what is the q and what is the option

Answer 18

oh, hold on, I'll repost

Answer 19

If the equation, C2H5OH (l) + 3O2 (g) arrow 2CO2 (g) + 3H2) (l), were performed in a laboratory at room temperature, both of the gas volumes:
(a) would depend on the surrounding temperature and pressure conditions
(b) must always be equal because the molar ratios are the same
(c) must always be equal because the number of representative particles is the same in the equation
(d) could be calculated without regard to the temperature and pressure surrounding them

Answer 20

It's a multiple choice question

Answer 21

@Abhisar @Somy @aaronq

Answer 22

Can you rule any of the options out given that they dont make sense?

Answer 23

b and c

Answer 24

I THINK d is correct..since it's room temperature you don't need to factor those things in..right?

Answer 25

nope, gases are \(\large \sf always\) dependent on temperature and pressure.

Answer 26

youre right about b and c though

Answer 27

ahh..so a is correct

Answer 28

Thanks aaronq, you're a lifesaver