Question

What is the 43rd term of an arithmetic sequence with a rate of increase of -6 and a11 = 12?
A)-174
B)-176
C)-180
D)-186
E)-240

Answer 1

@caleb_gajewsky

Answer 2

_>_<_

Answer 3

I don't understand the "a11 = 12" part :/

Answer 4

\[a ^{11} =12\]

Answer 5

@dan815

Answer 6

sorry qt

Answer 7

\[a_11=12 \\ a_12=12-6=6\\a_{13}=6-6=0 \\ a_{14}=0-6=-6\\
a_{15}=.....\\.\\.\\.\\.\\ a_{43}=?\]

Answer 8

how many times will we hhave to subtract 6? to get from term 11 to term 43

Answer 9

Think about that and get back to me with the answer :)

Answer 10

idk

Answer 11

omg idk and im stuck on a test todays the last day please give me the answers i know normally you shldnt and normally i dont ask for just answers but i need them now omg D:

Answer 12

okay lets see how many numbers are betwen 11 to 43

Answer 13

*summer* T_T

Answer 14

pay attention then

Answer 15

omg im about to fail

Answer 16

-186?

Answer 17

we are subtracting from the 12th term so...
12 to 43 is how many numbers
if i subtract 11 from 12 and 11 from 43, that wont change the total numbers i have
12-11 to 43 -11
1 to 32 <---- so there are a total of 32 numbers between from 12 to 43

Answer 18

i have 1 more minute to answer this question

Answer 19

we are subtracting
32 times from 12
12-(32*6)=-180

Answer 20

it logged me out before i could finish omg D;

Answer 21

but thanx i know how to do it now

Answer 22

:) dont feel bad

Answer 23

*hug*

Answer 24

*runs his fingers through his beautiful hair*

Answer 25

lol