Question

Find the 11th partial sum of the summation of negative 7i plus 22, from i equals 1 to infinity.

Answer 1

\[\sum_{i=1}^{\infty}-7i+22\]

Answer 2

\[\Large\rm \sum_{i=1}^{11}-7i+22=\sum_{i=1}^{11}-7i+\sum_{i=1}^{11}22\]
\[\Large\rm =\sum_{i=1}^{11}-7i+11(22)\]

Answer 3

That second pard simplifies down nicely.
For the first part,
\[\Large\rm -7\sum_{i=1}^{11}i=-7(1+2+...+11)\]

Answer 4

mk :) then what

Answer 5

\[\Large\rm =-7(1+2+...+11)+11(22)\]Just bust our your calculator from that point I guess :

Answer 6

what are the ... for?

Answer 7

To show a continuation.
I didn't want to type out 1+2+3+4+5+6+7+8+9+10+11.
That's what the dots are implying.

Answer 8

ohhhh ok thanks

Answer 9

i dont get what the answer is?