How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 43.6 grams of sodium hydroxide in the single replacement reaction below? Be sure to show the work that you did to solve this problem.

Question

anonymous · Answer

unbalanced equation: Na + H2O yields NaOH + H2

anonymous · Answer

is my working correct

anonymous · Answer

balanced equation: 2Na + 2H2O yields 2NaOH + H2
43.6gNaOH*1molNaOH/40gNaOH=1.09molNaOH*2molNa/2molNaOH=1.09molNa*23gNa/1molNa=25.0gNa
density=mass/volume
volume=mass/density
volume Na=25g/0.97g/mL=25.8mL

anonymous · Answer

2Na + 2H2O ------------ 2NaOH + H2 
molar mass 46 2 
mass ? 43.6 
then the mass of sodium=46×43.6÷2=1002.8 g 
Then the volume=1002.8/0.97=1033.8 ml