1. Use the given specific heat capacity values below to calculate the percent error of the experimental specific heat capacity that you determined in Part I of the lab.

Known specific heat values — Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C
| experimental - actual value | x 100 %
actual value

I have aluminum.

Question

1. Use the given specific heat capacity values below to calculate the percent error of the experimental specific heat capacity that you determined in Part I of the lab.

Known specific heat values — Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C
| experimental - actual value | x 100 %
actual value

I have aluminum.

anonymous · Answer

This is so far what I have:
$$\left| 0.8628 - 0.900 \right| *  1.0$$

somy · Answer

oh why didn't you tag me lol

anonymous · Answer

i didn't want to keep bothering you with my questions >.<

somy · Answer

oh no its okay))

somy · Answer

hmmm i don't really know it but im guessing this way 
0.900-- 100%
0.900-0.8628---X%

so find X% this will be the error

somy · Answer

that's what im guessing it should be like but lets cross check just in case  
@iPwnBunnies

anonymous · Answer

i'm looking at the worksheet and i'm so confused because they want me to guess what metal i used but nothing adds up. :(( lol

ipwnbunnies · Answer

Yeah, if you multiply the difference by 100%, you should get the error.

somy · Answer

no its not really guessing

somy · Answer

specific heat capacity value that we got in part 1 is closest to Al value

somy · Answer

and even the question is mentioning that there will be some error  meaning you will not get a perfect answer that will match any of these metals

anonymous · Answer

i got 7.7652 but I have no clue if I did it right

somy · Answer

hmmm 
X= ((0.900-0.8628)* 100)/ 0.900

somy · Answer

did u do it this way?

somy · Answer

im getting 4.13%

anonymous · Answer

i did
0.8628 - 0.900 x .001

somy · Answer

what is this?? is this some kind of formula?

anonymous · Answer

i used experimental - actual value x 100%

somy · Answer

hmmm let me check this formula

anonymous · Answer

ok

somy · Answer

your formula is wrong 
the formula is 

% error= ( (Actual- experimental)/actual ) * 100

somy · Answer

you get exactly same answer as i did just using mathematical common sense

somy · Answer

tell me what you don't understand so that i clear it up :)

anonymous · Answer

i got 90?

i did .8628 - .900/.8628 x 100

.77652/.8628 x 100

.9 x 100 = 90

somy · Answer

Actual is the value that it 0.900 
Experimental is the value we got

anonymous · Answer

i did this backwards im sorry sigh :/

somy · Answer

its okay )

anonymous · Answer

now i got 4.13! lol

somy · Answer

good :D

anonymous · Answer

can you help me with another question? i'll open a new question

somy · Answer

okay) just tag me:)