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Mathematics 8 Online
OpenStudy (anonymous):

A random sample of 145 students is chosen from a population of 4250 students. IF the mean IQ in the sample is 130 with a standard deviation of 7, what is the 90% confidence interval for the students IQ score? A 98.98-101.02 B 109-112 C 125-135 D 129.05-130.95

OpenStudy (amistre64):

how many of them have a mean of 130 ....

OpenStudy (anonymous):

It doesn't say :/

OpenStudy (amistre64):

since A and B dont even contain 130, then cant possibly be it

OpenStudy (anonymous):

yea im thinking D, just want to be sure

OpenStudy (amistre64):

d might not be quite right

OpenStudy (amistre64):

you recall how to find a zscore?

OpenStudy (anonymous):

How should i check? without numbers im a big confused how to do it lol

OpenStudy (amistre64):

we want to know how many standard deviations fit between the mean, and an end point

OpenStudy (amistre64):

\[\frac{endpoint-130}{7}\]

OpenStudy (amistre64):

we need to be between 1 and 2 since they represent 65 and 95 percent of the data

OpenStudy (amistre64):

.95/7 is less then 1 5/7 seems a better fit, but this is without any real calculations

OpenStudy (amistre64):

but a memory is forming .... might have to multiply by the sqrt of the sample size

OpenStudy (amistre64):

\[\bar x\pm Z_{.9500}(7/\sqrt{n})=\mu\]

OpenStudy (anonymous):

so by 65.19?

OpenStudy (amistre64):

not 95% .... 90% which i think has a z of 1.576 or thereabouts

OpenStudy (amistre64):

no 130+1.576(7/sqrt(145)) yeah, d is looking better now

OpenStudy (anonymous):

alright good, because your equations look alot better than mine do lol

OpenStudy (amistre64):

when looking for a mean of a mean we use the sample error which is just a modified version of the standard deviation

OpenStudy (anonymous):

Thanks for the help amistre, youre the best man

OpenStudy (amistre64):

good luck :)

OpenStudy (amistre64):

yeah, d is our choice

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