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the equation r=3sin theta represents a circle. find the cartesian coordinates of the center
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\[\Large\rm r=3\sin \theta\]Umm I can show you the way `I would do it`. There's probably a shorter way.. but this is what makes sense to me at least...
Multiplying both sides by r gives us,\[\Large\rm r^2=3r \sin \theta\]Then recall how we change things from polar to cartesian,\[\Large\rm r^2=x^2+y^2\]\[\Large\rm x=r \cos \theta\]\[\Large\rm y=r \sin \theta\]
So plugging in some stuff for the r^2 and r sin theta,\[\Large\rm x^2+y^2=3y\]
Move the y's to the left, and complete the square on the y's.\[\Large\rm x^2+y^2-3y=0\]Remember how to complete the square?
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