Question

Using the specific heat capacity value that you determined in Part II of the lab, what is the most probable identity of the unknown metal that you examined? Please explain your reasoning in complete sentences.

I got .0054 as the heat capacity and I have no clue what to do from there.

Answer 1

@Somy

Answer 2

is it new experiment?

Answer 3

I answered this question

Using the formula qunknown metal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation. Show ALL your work.
Q= 25 x 4.18 x (29.1 – 25.2)
q= 25 x 4.18 x 3.9
q= 407

407= 25.605 x c x (100.3 – 29.1)
407= 25.605 x c x 2918
407= 74715 x c
407/74715= 74715/74715 x c
.0054 = c

Answer 4

good job!!!!

Answer 5

okay so what are the values given as specific heat capacities?

Answer 6

what metals and what values?

Answer 7

hehe thank you I was able to answer it with your help on a previous question :)

Answer 8

this is all that was given

Known specific heat values — Iron: 0.444 J/g°C; Zinc: 0.390 J/g°C; Copper: 0.385 J/g°C, Aluminum: 0.900 J/g°C

Answer 9

alright the value that u got is too small
let me recheck the calculation

Answer 10

I thought so sigh

Answer 11

found your mistake :)

Answer 12

407= 25.605 x c x (100.3 – 29.1)
407= 25.605 x c x 2918
407= 74715 x c
407/74715= 74715/74715 x c
.0054 = c

Answer 13

2918
what is this?

Answer 14

(100.3 – 29.1)= 71.2

Answer 15

I keep getting 2918.73??

Answer 16

how? something is wrong
its subtraction
r u multiplying?

Answer 17

round the value of q to 408 J
because the value u get is 407.55

Answer 18

Q= mc Delta T

lets make C as subject

C= Q/ mDelta T

Answer 19

Delta T for metal will be 100.3-29.1= 71.2
m= 25.605
Q= 408 J

Answer 20

now put the values into the formula

Answer 21

i got .2232

Answer 22

yeah 0.2233 basically

Answer 23

no the closest value to the one we are getting is Copper: 0.385 J/g°C

Answer 24

are you getting it?

Answer 25

yeah!

Answer 26

good :)

Answer 27

so what are u getting as error?

Answer 28

42

Answer 29

good job :))

Answer 30

thank you!

Answer 31

u r welcome :))

Answer 32

I have one last question and I just need help understanding what they're asking me

Answer 33

okaay :) np post a new q :)