Question

PLEASE HELP!!!!!! IM DOING SIGMA NOTATIONS

Answer 1

i believe its

sigma: a1(r)^(n-1)

Answer 2

thats the general formula yes ... can we narrow it down anymore?

Answer 3

ummm 42(3/4)^n-1?

Answer 4

that looks correct to me, but sigma notation is not a strenght..

Answer 5

yes, now does it diverge, or do you think it settles down to a value?

Answer 6

I don't really know when a summation diverges or can settle

Answer 7

if the absolute value of the common ratio is less than 1 .... it will settle down

Answer 8

we can formula a summation function as:\[a_1\frac{1-r^n}{1-r}\]
as n to infinity, the only hope of this settling down is if r^inf is zero.

Answer 9

so it can

Answer 10

only fractions between 0 and 1 will zero out

Answer 11

so 42(1-(3/4))^n/1-3/4)?

Answer 12

yes, but n=infinity so its more of 42/(1-3/4)

Answer 13

since you only have 2 options that are somewhat valid, it either diverges or it converges to 168 ... since its NOT divergent ....

Answer 14

it converges! :D lol thank you!!!

Answer 15

yw