Question

What is the equation of a line that passes through (-6, 2) and has a slope of −1/2 ?

Answer 1

\[y-y _{1}=m(x-x _{1})\]

Answer 2

where m= slope, y1= y coordinate, and x1 = x coordinate

Answer 3

plug in the information you have been given and solve for y

Answer 4

Hi :)

Slope-intercept of a line: \(\LARGE y=mx+b\) where m=slope, be is the y-intercept.
Standard equation of a line: \(\LARGE Ax+By=C\)

which form do you need?

Answer 5

this is the choices
..A) y=x2−2

B) y=−x2−1

C) y=2x+1

D )y=−2x−1

Answer 6

i would recommend point slope form then

Answer 7

Use the point slope form \(y-y _{1}=m(x-x _{1}) \)
Put this into slope intercept form \(y-2=\frac{1}{2}(x-(-6)) \)

Answer 8

yes, like @MDoodler from there, solve for y

Answer 9

I'm lost..

Answer 10

alright i will try to explain it.

Answer 11

point slope form uses a given point {in your case (-6, 2)}

Answer 12

and the slope (in your case -1/2)

Answer 13

and by using \[y-y _{1}=m(x-x _{1})\] you can find your equation in the form or y=mx + b which is called standard form

Answer 14

so in your case, -6 = your x1
2 is your y1
and -1/2 is your m

Answer 15

try putting those values into your equation

Answer 16

y = mx + b is not standard form TechnoSoul.l That form is slope intercept form.

Answer 17

you should end up with \[y-2=-1/2(x+6)\]

Answer 18

sorry, ya. slope-intercept form. my bad

Answer 19

Its fine I think I get it now

Answer 20

alright, once you get your answer, you can write it here and i can check that its correct if you want

Answer 21

so I times -1/2 and 6?

Answer 22

yes good

Answer 23

by now, you should have something that looks like \[y-2=-1/2x-3\]

Answer 24

if you dont have that i can explain what i did

Answer 25

and then from there add 2 to both sides and you have your equation

Answer 26

okay i got y=1/2x-1

Answer 27

wait its y=x/2-1 right?

Answer 28

yes it is good job :)

Answer 29

Thanks!!

Answer 30

sure thing