What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x + y - 2 = 0?
alright so i would recommend first putting your given equation into slope-intercept form
to do that you just need to subtract the 4x on both sides and add the 2 to both sides as well
so now you should have y = -4x + 2. the reason i did this is because i find it easier to know the slop when it is in this form
when in y = mx + b form the way we have it, the m or in your case the -4 is the slope
because you are looking for a line parallel to this one, it will have the same slope so we have our m
now, i would recommend using point slope form which is\[y-y _{1}=m(x-x _{1})\]
where y1 is your y coordinate and x1 is your x coordinate
so for (4, -3) with a slope of -4, your equation should look like \[y+3=-4(x-4)\]
from there, solve for y
i would recommend distributing the -4 first for this and then subtracting the 3
once youve done that you should get \[y=-4x+13\]
and that would be your answer
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