Which of the following is a possible set of quantum numbers for an electron n, l, m subscript l, m subscript ? (1, 0, 0, +1) (2, 2, 1, +½) (4, -3, 0, -½) (3, 2, 1, -½)
@iPwnBunnies can u help me?
@sweetburger can u help me?
@abb0t can u help me?
@iPwnBunnies
'n' can be any number from 1 to some high number that I'm not sure about. 'l' would be every number from 0 to (n-1) 'ml' will be numbers -l to +l. 'me' will be either -1/2 or 1/2. :3 You can go through these conditions and possibly cross out some of them.
'ms' not 'me', for isospin.
so would it be the first option?
Nope. If you look at the first option, you can immediately rule it out. The number at the end is +1, which is supposed to be number 'ms'. 'ms' can only be 1/2 and -1/2
i know it is not c
Why do you think it's not C?
because -3 is not an i.e. of -3 the i.e of 4
sorry i mean -3 is not an i.e of 4
Err, yeahhh. o.o n = 4, So, the only numbers for 'l' can be 0, 1, 2, and 3. No negative numbers. :3
i stuck so with that being said is the answer be b.
.-. You're not following the guidelines for quantum numbers I gave you.
wait huh?
:33 I posted the guidelines to defining quantum numbers above. ...n can only be numbers 1 to something 'l' can only be numbers 0 to (n-1), it depends on number 'n'. etc.
oh so than it is d. because the first option has a negative number right?
The third option has the negative number. :3
oh yea that what i meant lol sorry so it is the 1st one
;-; I already explained why it's not choice A. The last number is +1, which is the isospin number. It can only be 1/2 and -1/2.
1/2 or -1/2*
oh sorry so is it D
Yesh, it'll be D. :3
yay! Thank you berry much!
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