Question

Use the discriminant to determine the nature of the roots of x2 = 0.

Answer 1

A no real roots B one real root
C two distinct real roots D three distinct real roots

Answer 2

x^2=0

Answer 3

\(\bf x^2 = 0\implies {\color{blue}{ 1}}x^2{\color{red}{ +0}}x{\color{green}{ +0}}=0\qquad discriminant\to
\sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}\)

http://www.regentsprep.org/Regents/math/algtrig/ATE3/discriminant.htm

Answer 4

im so confused

Answer 5

well what did you get for the discriminant?

Answer 6

0

Answer 7

well so ohh shoot... ahemmm the discrimoiant should only be \(\bf {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}\) not root, my bad

so notice, when you get 0, on the site on the link, it has a guideline for when it's + or - or 0

Answer 8

yes

Answer 9

so, 0 means only 1 real root :)

Answer 10

since i got zero does that mean there's only one

Answer 11

ohhh :P

Answer 12

hehe

Answer 13

can i ask u another?? :)