Question

Let f(x) = x^2 + 6 and g(x) =x+8/x. Find ( g o f)(-7)

Answer 1

find f(-7) first, ie plug in x=-7 into f(x)

then plug that result into g(x)

Answer 2

f(x)=-7^2+6?

Answer 3

Yes. Brackets around -7.

Answer 4

55?

Answer 5

Yes, now plug that into g(x)

Answer 6

x would be 55 in g(x) ?

Answer 7

Yes

Answer 8

55+8/55? i got 1.14

Answer 9

I have no idea, you need to make sure to use brackets for g(x) =x+8/x because I can't tell what it is like that

Answer 10

g(x)= (55)+8/(55)? So i would get 63/55?

Answer 11

Thats my answer right? :)

Answer 12

No, i mean, make it clear what it is. is g(x) =x + 8/x or g(x) =(x+8)/x

Answer 13

\[\large g(x) =x+\frac{ 8 }{x} \text { ..... or ..... } g(x) =\frac{x+8 }{x} \]

Answer 14

second one

Answer 15

Then use brackets, g(x) =(x+8)/x,

since the g(x) =x + 8/x means the first one.

Answer 16

So 63/55 isnt my answerr?

Answer 17

lol its one of my choices

Answer 18

Plug in 55 into your function, the correct one, and check :P

Answer 19

g(x)= (55+8)/55 ?

Answer 20

Its the same thing right?

Answer 21

Yes, simplify it

Answer 22

But thats my answer like that just like that 63/55 :P Its A:)

Answer 23

lol yes, i was just making sure you KNEW it was your answer! :P

Answer 24

oh haha okay :) thanks :)

Answer 25

haha no prob :)