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Mathematics 17 Online
OpenStudy (anonymous):

Simplify The Equation Below

OpenStudy (anonymous):

\[4\sqrt{4} \over \sqrt{7}\]

OpenStudy (mathmate):

Mathematicians do not like seeing square roots in the denominators, because they make addition and subtraction of fractions messy. The process to remove them (and keep the same value of the expression) is called rationalizing the denominator. In this case, we only have to multiply top and bottom by sqrt(7): \[\frac{4\sqrt4}{\sqrt7}\frac{\sqrt7}{\sqrt7}\] \[=\frac{4\sqrt4\sqrt7}{7}\] \[=\frac{4\sqrt{28}}{7}\] That's about all we can do to simplify the expression.

OpenStudy (anonymous):

wow, so easy!

OpenStudy (anonymous):

Thanks Man! @mathmate

OpenStudy (mathmate):

You're welcome! ::)

OpenStudy (e.mccormick):

Nope. \(2=\sqrt{4}\) so you can take that out from under the root to start.

OpenStudy (e.mccormick):

Simplifying roots is an exercise in prime factoring and removing sets.

OpenStudy (mathmate):

Thank you @e.mccormick I was preoccupied and overlooked it. Thank you so much.

OpenStudy (e.mccormick):

Yah, happens. Hehe. I told someone stuff about area of a triangle because of a graph... and it was supposed to be area of a rectangle inscribed in the triangle! We all miss things at times.

OpenStudy (mathmate):

Yep! Totally agree! Happens to everyone!

OpenStudy (e.mccormick):

\(\dfrac{4\sqrt4}{\sqrt7}\cdot\dfrac{\sqrt7}{\sqrt7}\implies \dfrac{4\sqrt{2\cdot 2\cdot 7}}{\sqrt{7\cdot 7}}\implies \dfrac{4\cdot 2\sqrt7}{7}\) so in the end: \(\dfrac{8\sqrt7}{7}\)

OpenStudy (mathmate):

Yep, perfect!

OpenStudy (e.mccormick):

Yah, explains what I meant by prime factors being the key to reducing roots.

OpenStudy (mathmate):

@AjMJackKnife please check correction!

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