If sue can shovel the driveway in 50 minutes and jim can do it in 60, how long would it take for both of them to do it together?
you wanna do it the real quick snap way?
using only the two numbers given to you, and no equation at all compute \[\frac{50\times 60}{50+60}\]
i can explain why that is the right answer if you like, but that is all you really have to do here
Would you mind explaining for me please?
ok sure but first is it clear what we are going to compute at the end of the explanation?
Sorta...
\[\frac{50\times 60}{50+60}=\frac{3000}{110}=\frac{300}{11}\] or your can write it as a mixed number \[27\tfrac{3}{11}\]
now that we see how easy it is, ready for the explanation?
Yes!
ok sue can shovel the driveway in 50 minutes that means her rate is \(\frac{1}{50}\) of the job per minute jim can do it in 60 minutes his rate is \(\frac{1}{60}\) of the job per minute
their combined rate is what you get when you add them and \[\frac{1}{50}+\frac{1}{60}=\frac{50+60}{50\times 60}\]
i am not going to compute this number just leave it alone
then since that is their rate, \(\frac{50+ 60}{50\times 60}\) you want the time it takes to complete one job, in other words you want to solve \[\frac{50+60}{50\times 60}T=1\] for \(T\) and you solve for \(T\) by multiplying by the reciprocal so \[T=\frac{60\times 50}{50+60}\]
you do more than two of these you can go straight to the answer while all your colleagues are trying to write down some equation
Wow thank you so much I really appreciate the help!!!
yw
hope it is more or less clear
it was very clear,, better than how my teacher explained it
lol thanks!
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