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Mathematics 13 Online
OpenStudy (anonymous):

I need help please!

OpenStudy (anonymous):

I need see the problem, please!

OpenStudy (anonymous):

Quadrilateral ABCD is located at A (-2,2), B (-2,4), C(2,4), and D (2,2). The quadrilateral is then transformed using the rule (x+7, y-1) to form the image A'B'C'D'. What are the new coordinates of A', B', C', and D'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

OpenStudy (anonymous):

Sorry! @opps :) I just posted it

OpenStudy (anonymous):

@oppps

OpenStudy (anonymous):

@Ooops

OpenStudy (anonymous):

new cooedinates will be A'=(5,1) B'=(5,3) C'=(9,3) D'=(9,1) TO FIND A' use A(-2,2) now on x-coordinate apply x-xrdinate term of exchang rule.i.e x+7 ,so as in A x=-2 so put -2 in rule you aill get x-coordinate of A'..i.e. -2+7=5 to find y of A'.use y of xchange rule..that is y-1.as in A y=2, so it will be 2-1=1 so you have A'=(5,1) others can be done on same steps...

OpenStudy (anonymous):

got him?

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