What is the quantum number set of the ground-state electron that is found in lithium (Li) but not in helium (He)? (1, 0, 0, +½) (1, 0, 1, +½) (2, 0, 0, +½) (2, 0, 1, +½)
@Abhisar how do you do this?
2\(s^1\) electron
Can u find the quantum number this ?
um it don't know how
It's simpler 2 will be principle quantum number, 0 will be Azimuthal quantumn number (l), 0 will be magnetic quantum number (\(\huge m_l\)), =+1/2 will be spin quantum number (\(\huge m_s\))
Got it ?
can you tell me how to set it up?
u know to find out 4 quantum numbers ?
yes 0 to (n-1)
that is the formula for finding l (one of the 4 quantum numbers)
o
I told u to read ur textbook. U read that ?
i don't have a textbook I am doing online studying
then u must be having an e-book
I don't
Then how do u study ?
i read lessons but they don't make any sense to me:(
read this https://in.answers.yahoo.com/question/index?qid=20080712213516AA3SiwM
ok it makes more sense
l = 0 to n-1. Hence, it can have values 0, 1, 2. m = -l to +l. Hence, it can have values -2, -1, 0, 1, 2 s = +1/2 and -1/2 i don't understand this part
@Abhisar
all three ?
yes :l
What is giving u trouble ?
wait so if you solve the problem is your answer the third option?
@radar
yes it is the third one
:)
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