Question

write the equations in slope intercept and standard form:

perpendicular to 3x+4y=13 and through (2,7)

parallel to y= -5 and through (2,7)

vertical and contains (-4,6)

x-intercept= 2 and y-intercept= -4

Answer 1

slope intercept form y = mx + b
for any point on the line (x,y) m = slope and b= y-intercept (when x = 0)

standard form Ax + By = C A,B and C are real numbers

parallel lines have the same slope

for perpendicular lines the product of the slopes is -1

now go through each problem with this in mind

Answer 2

ok, thanks. but for the parallel problem, there is no slope. so i would have to solve for slope first right?

Answer 3

and are you saying that for all perpendicular lines, the slope in -1?

Answer 4

no! the product of the slopes =-1

Answer 5

slope of line AB multiplied by slope of line PQ = -1 for lines AB and PQ

Answer 6

i still don't understand how i would solve the first problem with the information i am given. i know that the 3x+4y=13 is in standard form. but what would i do to get the standard form of the line it is perpendicular to??

Answer 7

m1*m2 = -1 where m1 is one slope and m2 is the slope of the perpendicular line

Answer 8

so how would i find the slope?

Answer 9

first rewrite to y = mx + b form
m = slope
let this slope = m1 the perpendicular let it be = m2 use m1*m2 = -1 to find m2
you have a point on the perpendicular line
find b then write the general eqn

Answer 10

i think i understand now. thank you so much!!

Answer 11

great
welcome

Answer 12

how would i solve for b??

Answer 13

use the point on the line (x.y) (2,7)

Answer 14

y = mx + b

Answer 15

thanks!

Answer 16

let me see when you have it in standard form

Answer 17

ok

Answer 18

b would be 7, right?

Answer 19

x+4y=28 is standard form

Answer 20

that's not what i got

Answer 21

b is 7, right??