Question

Given: AC and AE are common external tangents of G and D. BC =4, FE=26, GF=5 and AG=13.
What is the measure of AC.

Answer 1

sorry about that

Answer 2

@doulikepiecauseidont

Answer 3

trust us were professional

Answer 4

@doulikepiecauseidont

Answer 5

@skullpatrol

Answer 6

CAN SOMEONE HELP ME PLEASE

Answer 7

I can help you forreal this time.

Answer 8

Ok, well the question labeled FE incorrectly, actually if AE and AC are common external tangents then FE=BC

Answer 9

The common external tangent AC forms the base of a right triangle with CD as the height and AD as the hypotenuse. Also, AB is the base of another right triangle with GB as the height and AG as the hypotenuse.

Answer 10

They give us AG=13 and we know that GF which is 5=BG since they're both radii in the circle G so we have AB to solve for and that's a missing leg in a 5,x,13 triangle, that value of x is 12 since 5^2+x^2=13 solves for 12

Anyways add 12 (AB) to BC (which is 4) to get 12+4=16

Answer 11

SO WHATS THE ANSWER

Answer 12

I explained the whole question and gave you the answer at the end, I'm questioning if you're willing to work through these problems or just want the answers

Answer 13

I DONT UNDERSTAND TANGENTS AT ALL

Answer 14

The answer is 16. Do you understand right triangles?

Answer 15

its 38 actually

Answer 16

Your numbers are wrong in this question like I said, FE and BC can't be such different lengths they have to be equal

Answer 17

well i put 38 and it was right