Question

dy/dt = y^4 - 3y^3 + 2y^2
Medal for help!:)

a.What are the constant solutions of the equation
b. for what values of y is y increasing
c. for what values of y is y decreasing

I really just need someone check my work for errors.

I got for a.) 0, 1, 2
and b.) (0,1),(2,infinity)
and lastly c.) (-infinity,0),(1,2)

What do you guys think? Right or wrong? Please help, I'll give medal. I need to get my Calc grade up can you help me! :)

Answer 1

How did you obtain the constant solution? First you did integration. right! And then ?

Answer 2

I found the constants by setting the derivative to 0 (the equation to zero)

Answer 3

I think it by constant it means when the derivative is none, right?

Answer 4

OK. Then your constant solution is correct.

Answer 5

because there is no slope at these constant points, I checked a random point in between the constants and found the sign of the slope (plus or minus). But I am not sure if this is what the problem is asking? lol

Answer 6

What did you do for (b) ?

Answer 7

^ just what I said above, do you agree?

Answer 8

I have to turn in a 15 page packet, I just don't want to get anything wrong

Answer 9

Yes. you are absolutely right.

Answer 10

i'll take your word for it then, lol. thanks for your time

Answer 11

Wait... What about (b) ! I have not verified that.

Answer 12

I have constants 0,1,2 and I checked numbers in between all numbers.

I tested with -0.5, 0.5, 1.5, and 2.5

Answer 13

I plugged it into the equation. If it was negative then I assumed it was decreasing between tested points.

Answer 14

Right! Your all answers are correct. Good job!

Answer 15

thanks!